Lubricating Oil Demand Computing
| Use the occasion | The formula | Example |
|---|---|---|
 Ball bearings |
Oil demand F ( cc / hr ) = 0.04 x Bearing diameter x bearing number | Suppose there is a ball bearing, bearing diameter of 8, seeking hourly fuel injection. F = 0.04 x 8 x 1 = 0.32 ( cc / hr ) |
 Bearing |
Oil requirement F (cc / hr) = 0.0023 x bearing contact with the shaft diameter x length | Suppose there is a slide bearing, shaft 8, the contact length of the shaft 10, seeking hourly fuel injection.
F = 0.0023 x 8 x 10 = 1.84 ( cc / hr ) |
 Smooth bearing track |
Level:Oil requirement F (cc / hr) = 0.0017 x slide length x width slider
Vertical:Oil requirement F (cc / hr) = 0.006 x slide length x width slider |
Suppose you have a smooth dynamic bearing upright, slide length 10 width of 4, seeking hourly fuel injection.
F = 0.006 x 10 x 4 = 0.24 ( cc / hr ) |
 Cylindrical sliding bearing |
Oil requirement F (cc / hr) = 0.0023 x shaft diameter x shaft length | Suppose there is a cylindrical rolling body diameter of 8 to 10 long, seeking hourly fuel injection.
F = 0.0023 x 8 x 10 = 1.84 ( cc / hr ) |
 Linear Slides |
Oil requirement F (cc / hr) = 0.0012 x length x Slider Slider Number | Suppose there is a linear slide, slide a length of 8, the slider number is 2, seeking hourly fuel injection.
F = 0.012 x 8 x 2 = 0.19 ( cc / hr ) |
 Cam |
Oil requirement F (cc / hr) = 0.013 x circumference x width | Suppose you have a cam mechanism, the cam circumference 20, a width of 2, seeking hourly fuel injection.
F = 0.013 x 20 x 2 = 0.52 ( cc / hr ) |
 Gear |
Oil requirement F (cc / hr) = 0.046 x pitch diameter x tooth width | Suppose there is a spur gear, pitch circle diameter of 8, tooth width of 2, seeking hourly fuel injection.
F = 0.046 x 8 x 2 = 0.74 ( cc / hr ) |
 Chain |
Oil requirement F (cc / hr) = 0.008 x chain length x width | Suppose you have a chain length of 30, chain width is 0.8, seeking hourly fuel injection.
F = 0.008 x 30 x 0.8 = 0.19 ( cc / hr ) |